25y^4-40y^3+16y^2=0

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Solution for 25y^4-40y^3+16y^2=0 equation:


Simplifying
25y4 + -40y3 + 16y2 = 0

Reorder the terms:
16y2 + -40y3 + 25y4 = 0

Solving
16y2 + -40y3 + 25y4 = 0

Solving for variable 'y'.

Factor out the Greatest Common Factor (GCF), 'y2'.
y2(16 + -40y + 25y2) = 0

Factor a trinomial.
y2((4 + -5y)(4 + -5y)) = 0

Subproblem 1

Set the factor 'y2' equal to zero and attempt to solve: Simplifying y2 = 0 Solving y2 = 0 Move all terms containing y to the left, all other terms to the right. Simplifying y2 = 0 Take the square root of each side: y = {0}

Subproblem 2

Set the factor '(4 + -5y)' equal to zero and attempt to solve: Simplifying 4 + -5y = 0 Solving 4 + -5y = 0 Move all terms containing y to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -5y = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -5y = 0 + -4 -5y = 0 + -4 Combine like terms: 0 + -4 = -4 -5y = -4 Divide each side by '-5'. y = 0.8 Simplifying y = 0.8

Subproblem 3

Set the factor '(4 + -5y)' equal to zero and attempt to solve: Simplifying 4 + -5y = 0 Solving 4 + -5y = 0 Move all terms containing y to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -5y = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -5y = 0 + -4 -5y = 0 + -4 Combine like terms: 0 + -4 = -4 -5y = -4 Divide each side by '-5'. y = 0.8 Simplifying y = 0.8

Solution

y = {0, 0.8, 0.8}

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